开发:嘉居导入的柜名统一

pull/2010/MERGE
ChenX 2 years ago
parent 586c44ca4c
commit 77a271b780

@ -165,25 +165,25 @@ class JiaJuParse
this.RoomIdNameMap.set(room.ID, room.Name);
}
ParseProduct(product: JiaJu.ProductBase, parentName: string = "", parentRoomName: string = ""): TemplateRecord | Entity
ParseProduct(product: JiaJu.ProductBase, guiName: string = undefined, parentRoomName: string = ""): TemplateRecord | Entity
{
if (product.ObjType === "Board")//(product as JiaJu.EntityProduct).BoardMode
{
return this.ParseBoardParseBoard(product as JiaJu.EntityProduct, parentRoomName, parentName);
return this.ParseBoardParseBoard(product as JiaJu.EntityProduct, parentRoomName, guiName);
}
else if (product.ObjType === "Cabinet" || product.ObjType === "CabinetDoor" || product.ObjType === "Group")//组
// || product.TypeID === "" || product.TypeID === "GuiTi"
{
parentRoomName = this.RoomIdNameMap.get((product as JiaJu.ModelProduct).RoomID) ?? parentRoomName;
parentName = product.Name ?? parentName;
guiName = guiName ?? product.Name ?? "[未命名]";//柜名只能初始化一次
let template = new TemplateRecord().InitBaseParams();
template.Name = parentName;
template.Name = product.Name ?? "[未命名]";
this.curDb.TemplateTable.Add(template);
for (let p of (product as JiaJu.ModelProduct).Products[0].Product)
{
let obj = this.ParseProduct(p, parentName, parentRoomName);
let obj = this.ParseProduct(p, guiName, parentRoomName);
if (obj instanceof Entity)
template.Objects.push(obj.Id);
else if (obj instanceof TemplateRecord)

Loading…
Cancel
Save